Programming/Python
[Python] 딕셔너리 key, value 기준으로 정렬하기
henry-jo
2017. 10. 14. 17:37
#!/usr/bin/env python
# filename : dict_sort.py
from operator import itemgetter
dict = {}
dict['a'] = 2
dict['b'] = 1
dict['c'] = 5
print(sorted(dict.iteritems(), key=itemgetter(1), reverse=True))
- 결과
# python dict_sort.py
[('c', 5), ('a', 2), ('b', 1)]
#!/usr/bin/env python # filename : dict_sort.py from operator import itemgetter dict = {} dict['a'] = 2 dict['b'] = 1 dict['c'] = 5 print(sorted(dict.iteritems(), key=itemgetter(1), reverse=True))
결과
# python dict_sort.py
[('c', 5), ('a', 2), ('b', 1)]출처 : http://gauryan.blogspot.kr/2011/07/python.html